Question

What is the distance between(4,3) and (6,1)? Round to the nearest tenth.

Answer 1

You can solve this using the distance formula.

d =
`√((x_2 - x_1)^2 + (y_2 - y_1)^2)` Plug your coordinates into the formula
d =
`√((6 - 4)^2 + (1 - 3)^2)` Subtract inside the parentheses
d =
`√(2^2 + (-2)^2)` Simplify the exponents
d =
`√(4 + 4)` Add
d =
`√(8)` Simplify
d ≈ 2.8284 Round to the nearest tenth
d ≈ 2.8