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The diagonals of rhombus WXYZ intersect at point P. If WP = 12 and XP = 5, find the perimeter of the rhombus.

A.13
B.17
C.26
D.52

The diagonals of rhombus WXYZ intersect at point P. If WP = 12 and XP = 5, find the-example-1
User Antik
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2 Answers

2 votes
Answer: 52

Use the pythagorean theorum to calculate WX, since it's a rhombus, all sides are equal, multiply by four, finished.
User Afonso Tsukamoto
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8.7k points
1 vote

Answer with explanation:

WP=12 units

XP=5 units

Diagonals of rhombus bisect each other at right angles.as well as All sides of Rhombus are equal.

∠WPX=∠XPY=∠ZPY=∠WPZ=90°

Using Pythagoras theorem In Δ WPX

WX²=WP²+PX²

=12²+5²

WX²=144+25

WX²=169

WX=√169

WX=13 units

Perimeter of Rhombus WXYZ=4 × Side length (WX)

=4 × 13

= 52 Units

User Cameron Downer
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8.0k points

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