Question

Dave is meeting his friends at 7:30 PM. The average speed of the bus is 28 km/h, and he needs to travel 20 km. When is the latest time he should catch the bus?

Please explain in detail.

Answer 1

time= dist/speed

20/28 = 0.714 hrs

or 43 mins

7.30-43 = 6.57 pm

so any bus that leaves before 6.30 would get him there on time