Question

Please help.........​

Answer 1

-
`(61)/(11)`

Explanation:

`(x)/(y)` =
`(5)/(6)` ( cross- multiply )

6x = 5y ( divide both sides by 6 )

x =
`(5)/(6)` y

Then

`(5x+6y)/(5x-6y)` ← substitute x =
`(5)/(6)` y into the expression

=
`((25)/(6)y+6y )/((25)/(6)y-6y )`

=
`((61)/(6)y )/(-(11)/(6)y )`

=
`((61)/(6) )/(-(11)/(6) )`

=
`(61)/(6)` × -
`(6)/(11)`

= -
`(61)/(11)`