Question

A drawer contains 4 red socks, 3 white socks, and 3 blue socks. Without looking, you select a sock at random, replace it, and select a second sock at random. What is the probability that the first sock is blue and the second sock is red?

Answer 1

The probability that the first sock is blue and the second sock is red is:
(3/10) * (4/10)=3/25.

Answer 2

Probability = 0.12

Explanation:

Given : A drawer contain 4 red, 3 white , 3 blue socks

Total number of outcomes(S)= 10

Favorable event for first sock(B) ={3 blue sock}=3

Probability of picking first sock which is blue = favorable outcome/ total number of outcome P(B) = 3/10

since replacement is there

therefore, total no of outcomes remain same = 10

Favorable event for second sock(R) ={4 red sock}=4

then, probability of picking second sock which is red =favorable outcome/ total number of outcome P(R) = 4/10

Now, probability that the first sock is blue and the second sock is red is

P(B and R)= P(B) × P(R) = 3/10 ×4/10 = 12/100 = 3/25

Probability of events = 0.12