Question

What are the zeros of the polynomial function: f(x) = x3 + 10x2 + 24x ?

a.) –6, 0, 4
b.) 6, 0, –4
c.)–6, 0, –4
d.) 6, 0, 4

Answer 1

f(x) = x^3 –+10x^2 + 24x
x^3+ 10x^2 + 24x = 0
x(x^2+10x+24) = 0
x(x+4)(x+6) = 0
x= 0 or x = -4 or x =- 6
so the correct answer is C
hope it helps

Answer 2

The correct answer is: c.)–6, 0, –4

This is due to the following:

f(x) = 0


`x^(3)+10x^(2)+24x = 0`


`x · (x^(2) + 10x + 24) = 0`


`x^(2) + 10x - 24 = 0`


`x = \frac{- 10 +- \sqrt{10^(2)- 4 x 1 x 24}} {2}`


`x = \frac{- 10 + 2} {2} = -4`


`x = \frac{- 10 - 2} {2} = -6<span>`


`x = -6`


`x = -4<span>`


`x = 0`