14.0k views
1 vote
Find the limit as x approaches 0 of sin2x/4x.

1 Answer

2 votes
As we know that:

\lim_(n \to 0) (sinn)/(n)=1

\lim_(x \to 0) (sin2x)/(4x): (2)/(2)= \\ (1)/(2) \lim_(x \to 0) (sin2x)/(2x) = (1)/(2)*1 = (1)/(2)

User Dhaval Bhimani
by
7.4k points

Related questions

1 answer
2 votes
228k views