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What would be the pH of an HCl solution if the [H+] = 2.75 x 10-5 moles/liter?

User Icza
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HCl ⇄ H⁺ + Cl⁻

pH = - log [ H⁺]

pH = - log [ 2.75 x 10⁻⁵]

pH = 4.56

hope this helps!
User Girdeux
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I am absolutely sure that the pH of an HCl solution if the [H+] can be founded by the formula I have attached below. Quite an easy one and that is the only thing you need. Hope you still need the answer because this one is truly helpful.



pH = -lo[H+] log (2.75x10^-5) = pH of HCl = 4
User Mihai Stan
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