Question

PLEASE HELP SOON!!!!!;((((

Answer 1

ok so easy peasy
remember exponential laws

dividing

`(x^m)/(x^n)=x^(m-n)`
also
(ab)/(cd)=(a/c)(b/d)

also

`x^(-m)= (1)/(x^m)`
so

`(pq^7r^0)/(pq^7r) =( (p^1)/(p^1) )( (q^7)/(q^7) )( (r^0)/(r^1) )`=(1)(1)
`( (1)/(r) )`=
`(1)/(r)`=
`r^(-1)`

answer is
`r^(-1)`