Question

Determine how many moles are present in 0.23 kg of SO2.

Answer 1

1 kg ----- 1000 g
0.23 kg --- ?

0.23 x 1000 / 1 => 230 g

molar mass SO2 = 64 g/mol

1 mole --------- 64 g
? mole -------- 230 g

230 x 1 / 64 => 3.593 moles

Answer 2

`3.60~mol~SO_2`

Step-by-step explanation:

The first step is the conversion from Kg to g:

`0.23~Kg~(1000~g)/(1~Kg) = 230~g~SO_2`

Then we have to calculate the molar mass of
`SO_2`:

`O=~16~g/mol`

`S=~32~g/mol`

`SO_2=~(16x2)*(32*1)=~64g/mol`

`1~mol~SO_2=~64~g~SO_2`

With the molar mass is possible to calculate the moles:

`230~g~SO_2(1~mol~SO_2)/(64~g~SO_2) = 3.60~mol~SO_2`