180k views
17 votes
The price of Stock A at 9 A.M. was ​$12.79 Since​ then, the price has been increasing at the rate of ​$0.11 each hour. At noon the price of Stock B was ​$13.29 It begins to decrease at the rate of ​$0.12 each hour. If the two rates​ continue, in how many hours will the prices of the two stocks be the​ same?

pls pls pls

User Wonderer
by
8.4k points

1 Answer

3 votes

Answer:

2.174 hours

Explanation:

Let the number of hours be represented as:

x

The price of Stock A at 9 A.M. was ​$12.79 Since​ then, the price has been increasing at the rate of ​$0.11 each hour.

$12.79 + $0.11 × x

12.79 + 0.11x

At noon the price of Stock B was ​$13.29 It begins to decrease at the rate of ​$0.12 each hour.

$13.29 - $0.12× x

13.29 - 0.12x

Equating both equations together

Stock A = Stock B

12.79 + 0.11x = 13.29 - 0.12x

Collecting like terms

0.11x + 0.12x = 13.29 - 12.79

0.23x = 0.5

x = 0.5/0.23

x = 2.1739130435 hours

x = Approximately = 2.174 hours

If the two rates​ continue, the number of hours that the prices of the two stocks will be the​ same is 2.174 hours

User Igor Loskutov
by
8.3k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories