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Given a magnesium value of 4.5mg/dL, what is the result in SI units?

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Answer:


4.5x10^(-5)(kg)/(L)

Step-by-step explanation:

Hello!

In this case, since the density in the international system of units is given in terms of kg for the mass and L for the volume, we need to perform a process of units conversions from mg and dL to kg and L as show below:


4.5\frac{mg}d{L}*(1kg)/(1x10^6mg) *(10dL)/(1L) \\\\4.5x10^(-5)(kg)/(L)

Best regards!

User AKun
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