Question

if f(x) = 4 – x2 and g(x) = 6x, which expression is equivalent to (g – f)(3)? a: 6 – 3 – (4 3)2 b: 6 – 3 – (4 – 32) c: 6(3) – 4 32 d:6(3) – 4 – 32

Answer 1

f(x) = 4 - x^2
g(x) = 6x
(g - f)(x) = 6x - (4 - x^2)
(g - f)(3) = 6(3) - (4 - 3^2) = 6(3) - 4 + 3^2

Answer 2

Option c is correct

`6(3) - 4 +3^2`

Explanation:

Given the functions:

`f(x) = 4-x^2`

`g(x) = 6x`

We have to find
`(g-f)(3)`.

`(g-f)(3) = g(3) -f(3)`

Substitute x = 3 in the given functions we have;

`f(3) = 4 -3^2`

`g(3) = 6(3)`

Substitute these we have;

`(g-f)(3) = 6(3) - (4 -3^2)`

⇒
`(g-f)(3) = 6(3) - 4 +3^2`

Therefore, the value of
`(g-f)(3)` is,
`6(3) - 4 +3^2`