Question

What is the index of refraction of a substance if the critical angle for a ray going into Water (n=1.33) is 69.3°?1.2452.12.261.42

Answer 1

Given:

The refractive index of water is n1 = 1.33

The critical angle is

`\theta=69.3\text{ degrees}`

To find the refractive index of the substance.

Step-by-step explanation:

The refractive index of the substance can be calculated as

`\begin{gathered} n2\text{ =}\frac{n1}{sin\text{ }\theta} \\ =(1.33)/(sin(69.3^(\circ))) \\ =\text{ 1.42} \end{gathered}`

Thus, the refractive index of the substance is 1.42