Question

Find the sum. (2a2 + ab + 2b) + (4a2 − 3ab + 9)

Answer 1

`(2a^2+ab+2b)+(4a^2-3ab+9)\\\\=2a^2+ab+2b+4a^2-3ab+9\\\\=(2a^2+4a^2)+(ab-3ab)+2b+9\\\\=\boxed{6a^2-2ab+2b+9}`

Answer 2

The sum is
`6a^2-2ab+2b+9`

Explanation:

Given two expression

`(2a^2 + ab + 2b)` and
`(4a^2 − 3ab + 9)`

We have to find the sum of above two expression.

`(2a^2 + ab + 2b)+(4a^2 - 3ab + 9)`

Combining like terms we get

`(2a^2+4a^2)+(ab-3ab)+2b+9`

=
`6a^2-2ab+2b+9`

The sum is
`6a^2-2ab+2b+9`