Question

The sum of three consecutive integers is 120. What are the integers.

Find three consecutive integers such that the sum of the first and third equals the sum of the second and 21

Find four consecutive even integers such that four times the sum of the first and second is 8 less tgab 7 times the fourth

Answer 1

For question number 1, let the numbers be: x, x+2, x+4. So the formula would be: 120 = (x) + (x+2) + (x+4). The answer would be: x=38. So the integers are: 38,40, and 42.

For question number 2, let the numbers be x, x+1, x+2. So the formula would be: (x) + (x+2) = (x+1) + 21. The answer would be x=20. So the integers are 20, 21, and 22.

For question number 3, let the numbers be x, x+2, x+4, x+6. So the formula would be: 4(x + x + 2) = 8 - 7(x+6). The answer would be x=26. So the integers are 26, 28, 30, and 32.

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