Question

Only two horizontal forces act on a 3.0 kg body that can move over a frictionless floor. One force is 9.0 N, acting due east, and the other is 8.0 N, acting 62° north of west. What is the magnitude of the body's acceleration?

Answer 1

we can translate the given forces into their complex counterparts: 9.0 < 180 and 8.0 < 90-62. The mass of the object is converted to weight first by multiplying by 9.8 m/s2. The complex counterpart is 29.4 < 270. Adding the three forces, the resultant force is 25.7172 < -94.32 degrees.
Using second law of motion, F = ma ; a = 25. 7172 N / 3 kg = 8.5724 m/s2