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3 votes
Regular pentagon ABCDE rotates counterclockwise about its center to yield pentagon A'B'C'D'E'. At which angle of rotation does A' coincide with D?

A.320
B.288
C.216
D.144
E.72

User Bricktop
by
7.3k points

2 Answers

4 votes

Answer:


\left[\begin{array}{ccc}A&320\\B&288\\C&216&Correct\\D&144\\E&72\end{array}\right]


Point A Will Rotate To
PointD


PointT Will Rotate To
Point E.

Count How Many Points They Pass Through


\left[\begin{array}{ccc}PointA\\PointB&1\\PointC&2\\PointD\end{array}\right]


\left[\begin{array}{ccc}PointT\\PointA&1\\PointP&2\\PointE\end{array}\right]

Example Below

Regular pentagon ABCDE rotates counterclockwise about its center to yield pentagon-example-1
User Will Lopez
by
7.2k points
3 votes
The question is asking to choose among the following choices that state the angle of rotation does A' coincide with D, and base on my own calculation and further computation about the said pentagon, I would say that the answer would be E. 72. I hope you are satisfied with my answer and feel free to ask for more
User Teebot
by
7.2k points