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Simplify quantity 6 x plus 9 over 15 x squared all over quantity 16 x minus 12 over 10 x to the fourth power

User Shoshana
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2 Answers

4 votes

(6x + 9)/(15x^(2)) / (16x - 12)/(10x^(4))

(3(2x) + 3(3))/(3(5x^(2))) / (4(4x) - 4(3))/(2(5x^(4)))

(3(2x + 3))/(3(5x^(2))) / (4(4x - 3))/(2(5x^(4)))

(2x + 3)/(5x^(2)) / (2(4x - 3))/(5x^(4))

(2x + 3)/(5x^(2)) * (5x^(4))/(2(4x - 3))

(2x + 3)/(1) * (x^(2))/(2(4x - 3))

(2x^(3) + 3x^(2))/(8x - 6)
User Ritesh Singh
by
8.1k points
5 votes

Answer

Simplify the quantity 6 x plus 9 over 15 x squared all over quantity 16 x minus 12 over 10 x to the fourth power .

To prove

As given

the quantity 6 x plus 9 over 15 x squared all over quantity 16 x minus 12 over 10 x to the fourth power .

Now written this in the simple form


= \frac{(6x+9)/(15x^(2)){(16x -12)/(10x^(4))

Now simplify the above equation


= \frac{(6x+9* 10x^(4))/(15x^(2)* 16x-12)

Now using the property


(y^(a))/(y^(b)) = y^(a-b)

Thus


= \frac{(6x+9* 10x^(4 -2))/(15* 16x-12)


= \frac{(6x+9* 10x^(2))/(15* 16x-12)

Now again simplify the above equation


= (3(2x+3)* 10x^(2))/(15* 4(4x-3))

Thus


= ((2x+3)* x^(2))/(2* (4x-3))

Therefore


= \frac{2x^(3)+3x^(2)} {8x-6}

User Bae Cheol Shin
by
7.9k points

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