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What is the remainder when (3x4 + 2x3 – x2 + 2x – 14) ÷ (x + 2) ?

User Aliqandil
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2 Answers

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we are asked to find out the remainder when (3x4 + 2x3 – x2 + 2x – 14) is divided by (x + 2). In this case, we just have to substitute the numerator polynomial by the factor which is -2. Therefore, 3*(-2)^4 + 2*(-2)^3 – (-2)^2 + 2*-2 – 14 = 10
User Tassones
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1 vote

Answer:

Remainder: 10

Explanation:

Given:
(3x^4+2x^3-x^2+2x-14)/ (x+2)

We need to find the remainder of the division polynomial.

Using synthetic division:

-2 | 3 2 -1 2 -14 |

-6 8 -14 24

3 -4 7 -12 10

Please see the attachment for steps.

At last we get a number 10.

Therefore, 10 is remainder of division.

What is the remainder when (3x4 + 2x3 – x2 + 2x – 14) ÷ (x + 2) ?-example-1
User Dan Rubio
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