Question

24

Calculate the amount of heat in joules needed to increase the temperature of 350 g of water from 20°C to 56 °C. The specific heat of water is
4.18 J/gºc

Answer 1

To heat 350 g of water from 20°C to 56°C, 52,388.64 joules of heat energy is required, using the specific heat capacity of water which is 4.184 J/g°C.

Step-by-step explanation:

The question asks us to calculate the amount of heat needed to increase the temperature of a certain mass of water by a given number of degrees Celsius. To solve this, we use the formula Q = mcΔT, where Q represents the heat energy in joules, m is the mass of water in grams, c is the specific heat capacity of water, and ΔT is the change in temperature.

In this case, the mass (m) is 350 g of water, the specific heat capacity (c) is 4.184 J/g°C, and the temperature change (ΔT) is from 20°C to 56°C. Therefore, the temperature change (ΔT) is 56°C - 20°C = 36°C.

Now, we can calculate the heat energy (Q) required:

Q = (4.184 J/g°C) × (350 g) × (36°C)

Q = 52,388.64 J

Thus, 52,388.64 joules of heat energy is needed to increase the temperature of 350 g of water from 20°C to 56°C.

Answer 2

Q = 52668 J

Step-by-step explanation:

Given data:

Amount of heat required = ?

Mass of water = 350 g

Initial temperature = 20°C

Final temperature = 56°C

Specific heat capacity of water = 4.18 J/g°C

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 56°C - 20°C

ΔT = 36°C

Q = 350 g× 4.18 J/g°C ×36°C

Q = 52668 J