Question

A 68 g bar of gold is cut into 3 equal pieces. How does the density of each piece compare to the density of the original gold bar?

Answer 1

68/3=22.66 so its a third of the original density

Answer 2

The density would be same.

Explanation:

`\because \text{Density}=\frac{\text{Mass}}{\text{Volume}}`

Here, the mass of the original box = 68 g,

Suppose V be the volume of the original box,

Then, the density of the original box =
`(68)/(V)`

After cutting this box into 3 equal pieces,

Mass of each piece =
`(68)/(3)`

While, the volume of each piece =
`(V)/(3)`

So, the density of each piece =
`(68/3)/(V/3)` =
`(68)/(V)`

Hence, the density would be same.