107k views
1 vote
A jar contains five red marbles and three green marbles. A marble is drawn at random and not replaced. A second marble is then drawn from the jar. Find the probability that the first marble is red and the second marble is green.

1 Answer

3 votes
Probablility that that first marble is red:

P_(red) = (red)/(total)

P_(red) = (5)/(5+3)

Probability that the second marble is green:

P_(green) = (green)/(total(new))

P_(green)= (3)/(4+3) (because 1 red is now gone)


P_(total)=P_(red) * P_(green)

P_(total)= (6)/(8) * (3)/(7) = (18)/(56) = (9)/(28) \approx 32.1\%
User Sangram Barge
by
8.7k points