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F(x) = 4√(2x³-1) F'(x) =....?
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2 votes
F(x) = 4√(2x³-1)
F'(x) =....?

User Zsawaf
by
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1 Answer

5 votes

y= \sqrt[4]{(2x^3-1)} \\ y^4=2x^3-1 \\ 2x^3=y^4+1 \\ x^3= (y^4+1)/(2) \\ x= \sqrt[3]{(y^4+1)/(2)}

Therefore, F'(x) =
\sqrt[3]{(y^4+1)/(2)}
User Janisozaur
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