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4 votes
A medical battery loses 5% of its power each week. How long will it take until only 20% of

its power remains.

Answer if you only know

User Comatose
by
6.8k points

1 Answer

0 votes

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20=100(0.95)^t


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0.2=0.95^t


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Log \ 0.2 = t \ log.95


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(log0.2)/(log.95) = t


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31.4 \ weeks = t


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Hence \ solved
User Kilon
by
6.6k points