Question

Find the perimeter of the following shape, rounded to the nearest tenth:

12.5

15.7

16

16.5

Answer 1

so will be 5+5 + 2sqrt2 +2sqrt2 = 10 + 3 +3 = 16 rounded

hope helped

Answer 2

Option 2 - 15.7 unit.

Explanation:

Given : The image attached.

To find : The perimeter of the following shape?

Solution :

First we determine the coordinate of points,

A=(5,5)

B=(7,3)

C=(3,0)

D=(1,2)

Now, We apply distance formula to find the length of the sides.

`D=√((x_2-x_1)^2+(y_2-y_1)^2)`

The distance between AB,

`AB=√((7-5)^2+(3-5)^2)`

`AB=√((-2)^2+(2)^2)`

`AB=√(4+4)`

`AB=√(8)`

The distance between BC,

`BC=√((3-7)^2+(0-3)^2)`

`BC=√((-4)^2+(-3)^2)`

`BC=√(16+9)`

`BC=√(25)`

`BC=5`

The distance between CD,

`CD=√((1-3)^2+(2-0)^2)`

`CD=√((-2)^2+(2)^2)`

`CD=√(4+4)`

`CD=√(8)`

The distance between DA,

`DA=√((5-1)^2+(5-2)^2)`

`DA=√((4)^2+(3)^2)`

`DA=√(16+9)`

`DA=√(25)`

`DA=5`

The perimeter of the given shape is

`P=AB+BC+CD+DA`

`P=√(8)+5+√(8)+5`

`P=2√(8)+10`

`P=4√(2)+10`

`P=4(1.41)+10`

`P=5.64+10`

`P=15.64`

`P\approx15.7`

Therefore, Option 2 is correct.

The perimeter of the given shape is 15.7 unit.