Question

A proton is given an acceleration of 1.5x109 m/s² when it is placed in an electric field.

What is the strength of the electric field?

Answer 1

The strength of the electric field is
`E=15.66\: N/C`

Step-by-step explanation:

Here the electric force is equal to Newton's second law.

`F_(e)=ma`

Let's recall that electric force is the electric field times the charge, so we have:

`qE=ma`

`E=(ma)/(q)` (1)

Where:

m is the proton mass

q is the proton charge

a is the acceleration

Using the equation (1) we have:

`E=(1.67*10^(-27)1.5x10^(9))/(1.6*10^(-19))`

Therefore, the strength of the electric field is
`E=15.66\: N/C`

I hope it helps you!