Question

Use the graph given above, to find the slope and equation for the line.

Answer 1

The slope of a line is given by:

`m=(y_2-y_1)/(x_2-x_1)`

where (x1,y1) and (x2,y2) are two points through the line.

From the graph we notice that the line passes through the points (0,0) and (4,3). Plugging this values into the expression for the slope we have:

`\begin{gathered} m=(3-0)/(4-0) \\ m=(3)/(4) \end{gathered}`

Therefore the slope is 3/4.

Now, the equaiton of a line is given as:

`y=mx+b`

where m is the slope and b is the y-intercept. We already have the slope and from the graph we have that the y-intercept is zeo, then b=0. Plugging the values we have that the equation is:

`y=(3)/(4)x`