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Instructions: Find the missing side lengths. Leave your answersas radicals in simplest form.60°13

Instructions: Find the missing side lengths. Leave your answersas radicals in simplest-example-1
User Jhoanny
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1 Answer

25 votes
25 votes

To determine the missing side lengths we need first notice that this is a right triangle; we also notice that we know and angle and its adjecent leg.

Now, u is the hypotenuse of the triangle; to determine it we can use the cosine function which is defined as:


\cos\theta=(adj)/(hyp)

In this case we know that the angle is 60° and the adjecent leg is 13; then we have:


\begin{gathered} \cos60=(13)/(u) \\ u=(13)/(\cos60) \\ u=(13)/((1)/(2)) \\ u=26 \end{gathered}

Now, to determine the remaining length, v, we can use the pythagorean theorem which states that:


c^2=a^2+b^2

where a and b are the legs and c is the hypotenuse.

In this case the hypotenuse is 26 and one of the legs is 13, then we have:


\begin{gathered} 26^2=v^2+13^2 \\ v^2=26^2-13^2 \\ v^2=507 \\ v=√(507) \end{gathered}

Therefore, we conclude that:


\begin{gathered} u=26 \\ v=√(507) \end{gathered}

User Shrish
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