Question

1) if I have a 30 mole sample of gas at a temperature of 120˚C, and a volume of 300 L. What is the pressure of the gas on the container?

Answer 1

P = 3.23 atm

Step-by-step explanation:

Given data:

Number of moles of gas = 30 mol

Temperature = 120°C

Volume of gas = 300 L

Pressure of gas = ?

Solution:

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K

T = temperature in kelvin

Now we will convert the temperature.

120+273.15 = 393.15 K

P × 300 L = 30 mol × 0.0821 atm.L/mol.K × 393.15 K

P = 968.33 atm. L /300 L

P = 3.23 atm