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Trigonometry, find the missing angle!

Trigonometry, find the missing angle!-example-1
User Gcharbon
by
5.7k points

2 Answers

8 votes

Answer:

46

Explanation:

13.3 = H

9.2 = A

AH = cos

cos⁻¹(9.2÷13.3) = 46.23°

User Adam Vandenberg
by
5.9k points
7 votes

Answer:


\boxed {\boxed {\sf \angle z \approx 46 \textdegree}}

Explanation:

First, recall the three trigonometric ratios.

  • sin(θ)= opposite/hypotenuse
  • cos(θ)= adjacent/hypotenuse
  • tan(θ)= opposite/adjacent

13.3 is the hypotenuse because it is opposite the right angle. 9.2 is the adjacent because it is next to angle z. We must use cosine.

  • hypotenuse= 13.3
  • adjacent= 9.2

First, plug the values into the cosine ratio.

  • cos(z)=9.2/13.3

Divide.

  • cos(z)=0.691729323

Next, use the inverse of cosine because we are trying to solve for the angle.

  • z= cos⁻¹(0.691729323)
  • z= 46.23284386

Round to the nearest degree. The 2 in the tenth place tells us to leave the 6 in the ones place.

  • z≈46

Angle z is about 46 degrees

User Benedicta
by
6.0k points