Question

A new Youth Sports Center is being built in Hadleyville. The perimeter of the rectangular playing field is 536  yards. The length of the field is 22 yards less than quadruple  the width. What are the dimensions of the playing field?

Answer 1

W = 58 yards, L = 210 yards

Explanation:

P = 2 (L + W)

L = 4w - 22

P = 2 (4W - 22 + W)

536 = 8W - 44 + 2W

536 = 10W - 44

10 W = 536 + 44

10W = 580

W = 58 yards

Since L = 4W - 22

L = 4 (58) - 22

L = 232 - 22

L = 210 yards