Question

Write a balanced equation for the reaction of NaCH3COO (also written as NaC2H3O2) and HCl

Answer 1

`CH_3COONa~+~HCl~->~CH_3COOH~+~NaCl`

Step-by-step explanation:

This is an acid-base reaction in which the HCl is the acid and the
`CH_3COONa` is the base.

In the balanced reaction, we will have a double replacement reaction. In which the cation of
`CH_3COONa` (in this case
`Na^+`) will be exchanged by the hydronium ion
`H^+` from the
`HCl`. Similarly the anion of
`HCl` (
`Cl^-` ) would bond with the cation
`Na^+` to form
`NaCl`.

Answer 2

The chemical reaction of the reactants, NaCH3COO and HCl, is written as follows:

NaCh3COO + HCl = NaCl + CH3COOH

To balance it, the number of atoms of an element in one side should be equal to the other side. By looking at the reaction, I believe it is already balanced. They have 1 is to 1 ratios.