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If f is the function given by f(x)= integral from (4 to 2x) of sqrt(t^2-t)dt then f'(2) =?

2 Answers

3 votes
Hello,


f(x)= \int\limits^(2x)_4 {√(t^2-t) \, dt \\ (df(x))/(dx) = (df(x))/(d(2x)) * (d(2x))/(dx) =2* √((2x)^2-2x) \\ f'(2)=2 * √(4^2-4) =2* √(12) =4 √(3)
User Qutron
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The question ask to calculate the function f'(2) in the F is the function given by f(x) = integral from (4 to 2x) of sqrt(t^2-t), base on that, the possible answer would be that the f(2) is 4 sqrt 3. I hope you are satisfied with my answer and feel free to ask for more if you have questions 
User Eilistraee
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