Question

What is the volume of the container needed to store 0.8 moles of argon gas at 5.3 atm and 227°C?. . (Given: R = 0.08205 l · atm/mol · K). . 2.81 liters. . 4.39 liters. . 6.19 liters. . 9.67 liters

Answer 1

6.19 L

Explanation:

We are given that

Number of moles of argon gas=0.8 moles

Pressure =P=5.3 atm

Temperature =T=227 degree Celsius=
`227+273=500k`

We have to find the volume of the container needed to store the argon gas.

We know that

`PV=nRT`

Where R=0.082051 L atm/ mol k

Substitute the values in the given formula

`5.3* V=0.8* 500* 0.82051`

`V=(0.8* 0.082051* 500)/(5.3)=6.19 L`

Hence, the volume of container needed to store the gas=6.19 L

Answer 2

T = 227 ° C + 273 = 500 K
V = R n T/p = (0.08205 l atm/mol K * 0.8 mol* 500 K) / 5.3 atm = 6.19 lit
Answer: C ) 6.19 liters