Question

One number is six more than a second number. four times the first is 10 less than 6 times the second. Find the numbers.

I need this solves asap.

Answer 1

`\sf{\bold{\blue{\underline{\underline{Given}}}}}`

• One number is six more than a second number.
• four times the first is 10 less than 6 times the second.⠀⠀⠀⠀

`\sf{\bold{\red{\underline{\underline{To\:Find}}}}}`

• Find the two numbers.⠀

`\sf{\bold{\purple{\underline{\underline{Solution}}}}}`

⠀⠀⠀⠀

In questions given,One number is six more than a second number.

if second number is a

first number is a+6.

and,

four times the first is 10 less than 6 times the second.

So,

4×(a+6)=6a-10

we have to solve this.

`\bold{4* (a+6)=6a-10   }`

`\bold{4a+24=6a-10   }`

`\bold{6a-4a=24+10   }`

`\bold{2a=34   }`

`\bold{ a=(34)/(2)  }`

`\bold{ a=17  }`

we,get our second number =a=17.

So,

first number =a+6=17+6=23