Question

When looking at a rational function f of x equals the quantity x minus six times the quantity x plus three times the quantity x plus four all divided by the quantity x plus six times the quantity x minus three times the quantity x minus four, Jamal and Angie have two different thoughts. Jamal says that the function is defined at x = –6, x = 3, and x = 4. Angie says that the function is undefined at those x values. Who is correct? Justify your reasoning..

Answer 1

f ( x ) = ( x - 6 ) · ( x + 3 ) · ( x + 4 ) / ( x + 6 ) · ( x - 3 ) · ( x - 4 )
x + 6 ≠ 0, x ≠ - 6,
x - 3 ≠ 0, x ≠ 3,
x - 4 ≠ 0, x ≠ 4.
The function is not defined at : x = -6, x = 3 and x = 4.
Angie is correct.

Answer 2

Angie is correct

Explanation:

We have been given an expression:

`((x-6)(x+3)(x+4))/((x+6)(x-3)(x-4))`

We can see that function is undefined when we get in-determinant form that is denominator is zero.

Here, we can see that function is undefined at -6,3 and 4

Since, we will get value zero in denominator on all these points.

Hence, Angie is correct

And Jamal is incorrect.