Question

Solve these equations for the variable.
(4p-4)(13p+27)

Answer 1

p is approximately equal to 1.125, -1.925

Explanation:

We can solve this first by expanding, giving us a quadratic equation in the usual ax² + bx + c format, then solving that for p:

(4p - 4)(13p + 27) = 0

52p² + 108p - 52p - 108 = 0

52p² + 52p - 108 = 0

13p² + 13p - 27 = 0

13p² + 13p = 27

p² + p = 27 / 13

p² + p + 1/4 = 27/13 + 1/4

(p + 1/2)² = 108 / 52 + 13 / 52

(p + 1/2)² = 121 / 52

p + 1/2 = ± √(121 / 52)

p = -1/2 ± 11√(1/13) / 2

At that point we can simply plug those numbers into a calculator and solve it:

p ≈ 1.125, -1.925