Question

4) The components of Vector A are given as follows Ax = -2.4 Ay = + 3.8 What is the magnitude of the A, and what is the angle that A makes with the x axis​

Answer 1

A = 4.49

α = 57.72°

Step-by-step explanation:

Knowing the magnitude of x & y of a vector we can determine the total magnitude of a vector.

`A=\sqrt{A_(x)^(2) +A_(y)^(2) } \\A=\sqrt{(2.4)^(2) +(3.8)^(2) }\\A=4.49`

The angle tangent can be used to determine the angle.

`tan(\alpha )=(3.8)/(2.4)\\tan(\alpha ) =1.5833\\\alpha =tan^(-1)(1.5833) \\\alpha = 57.72 (deg)`