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4y-3=y+6 A.1 B.2 C.3 D.9
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3 votes
4y-3=y+6
A.1
B.2
C.3
D.9

User Gregyski
by
9.2k points

2 Answers

2 votes
4y - 3 = y + 6 |add 3 to both sides

4y = y + 9 |subtract y from both sides

3y = 9 |divide both sides by 3

y = 3

check:

L = 4 · 3 - 3 = 12 - 3 = 9
R = 3 + 6 = 9

L = R

Answer: C. 3
User NCFUSN
by
7.7k points
1 vote
If your are looking for y then y = 3

4y-3=y+6
Get your y's to one side then subtract from the right.
3y-3=6
Then move the minus three to the right.
3y=9
Then simply divide by three.
User Jason Harwig
by
8.0k points
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