Question

An object moves along a circular track of radius 3.00 m. The object completes one loop around the track in 4.00 s. Determine the centripetal acceleration of the object.

Answer 1

a = 7.4 m / s²

Step-by-step explanation:

The centripetal acceleration of an object that has constant speed is

a = v² / r

linear and angular velocity are related

v = w r

let's substitute

a = w² r

the angular velocity is related to the period

w = 2π / T

we substitute

a =
`(4\pi ^2 \ r)/(T^2)`

let's calculate

a = 4π² 3.00 /4²

a = 7.4 m / s²