Question

Only Part B(a) Calculate the minimum frequency of ultrasound (in Hz) that will allow you to see details as small as 0.175 mm in human tissue. (Assume the speed of sound through human tissue is 1540 m/s.) a = 8.8e6 (b) What is the effective depth (in cm) to which this sound is effective as a diagnostic probe? cm

Answer 1

To determine the maximum depth we will use the following rule:

`d_(max)=500\lambda`

Where:

`\begin{gathered} d_(max)=\text{ maximum depth} \\ \lambda=\text{ wavelength} \end{gathered}`

Now, we substitute the values:

`\begin{gathered} d_(max)=500(0.175mm) \\ d_(max)=87.5mm \end{gathered}`

Now, we convert to centimeters by dividing the result by 10:

`d_(max)=87.5mm*(1cm)/(10mm)=8.75cm`

Therefore, the maximum depth is 8.75 cm.