Question

Can someone help me with this system of equations

Answer 1

y =
`(1)/(2)`x + 3
y = x - 4

Since both equations are equal to y, you can set the two values equal to each other and solve for x.


`(1)/(2)`x + 3 = x - 4 Multiply both sides by 2
x + 6 = 2x - 8 Add x to both sides
6 = 3x - 8 Add 8 to both sides
14 = 3x DIvide both sides by 3
4
`(2)/(3)` = x

Now, plug the x value into one of the original equations, I'll plug it into y = x - 4.

y = x - 4 Plug in the x value
y = 4
`(2)/(3)` - 4 Subtract
y =
`(2)/(3)`

x = 4
`(2)/(3)` and y =
`(2)/(3)`