Question

In a geometric sequence, the first term is 6, the sum of infinity is 60, what is the common ratio?

Answer 1

Hello,


`u_(1) =6\\ \sum_(i=0)^\infty\6*q^i=60=6* (1)/(1-q) \\ (1)/(1-q) =10\\ 1-q= (1)/(10) \\ -q= -(9)/(10) \\ \boxed{q= (9)/(10) }`

Answer 2

the common ratio for this one should be -2 because it;s an infinite geometry