Question

If 2 L of gas has a pressure of 6 atm at 27⁰C. what is the temperature in Celsius if the pressure is decreased to 2.5 atm and the volume is changed to 0.66L?

Answer 1

3.7 degree celsius

Explanations:

According to ideal gas equation;

`(P_1V_1)/(T_1)=(P_2V_2)/(T_2)`

where:

• P1 and P2 are the initial and final pressure

,

• V1 and V2 are the initial and new volume

,

• T1 and T2 are the initial and final temperature

Given the following parameters

`\begin{gathered} P_1=6atm \\ V_1=2L \\ T_1=27^0C \\ P_2=2.5atm \\ V_2=0.66L \end{gathered}`

Required

Final temperature T2

Substitute

`\begin{gathered} T_2=(P_2V_2T_1)/(P_1V_1) \\ T_2=(2.5*0.66*27)/(6*2) \\ T_2=(44.55)/(12) \\ T_2\approx3.7^0C \end{gathered}`

Therefore the new temperature in Celsius is 3.7 degree celsius