Question

PLEASE HELP ME, WILL AWARD MEDAL

Answer 1

your answer is x+0 and x=-16

Answer 2

Hello,


`√(2x+4)- √(x) =2\\ ==\ \textgreater \ √(2x+4)=2+ √(x)\\ ==\ \textgreater \ 2x+4=4+4 √(x) +x \\ ==\ \textgreater \ x=4 √(x) \\ ==\ \textgreater \ x^2=16*x\\ ==\ \textgreater \ x^2-16x=0\\ ==\ \textgreater \ x(x-16)=0\\ ==\ \textgreater \ x=0 \ or \ x=16\\ Answer B`