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1 Srcl (aq) + 1 H,60,(aq) → 2 HCl(aq) + 1 Srso (s)

What is the mass of strontium chloride that reacts with 300.0 g of sulfuric
acid?

1 Answer

8 votes

Answer:

Mass = 245.72 g

Step-by-step explanation:

Given data:

Mass of SrCl₂ react = ?

Mass of H₂SO₄ = 300.0 g

Solution:

SrCl₂ + 2H₂SO₄ → 2HCl + Sr(HSO₄)₂

Number of moles of H₂SO₄:

Number of moles = mass/molar mass

Number of moles = 300.0 g/ 98.079 g/mol

Number of moles = 3.1 mol

Now we will compare the moles of SrCl₂ and H₂SO₄.

H₂SO₄ : SrCl₂

2 : 1

3.1 : 1/2×3.1 = 1.55 mol

Mass of SrCl₂:

Mass = number of moles × molar mass

Mass = 1.55 mol × 158.53 g/mol

Mass = 245.72 g

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