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5 votes
A bowler getting strike during a particular frame has an estimated probability of 41%. If several simulations of the bowler bowling 2 frames were performed, what percentage of the simulations would the bowler be most likely to get a strike in each of the two frames?

A. 61%
B. 38%
C. 18%
D. 81%

User Miga
by
8.4k points

2 Answers

5 votes

Answer:

Option C

Step-by-step explanation:

Given -

The probability of a bowler getting a strike during a particular frame
= 41 %
= 0.41\\

Solution:

Probability of a bowler getting a strike during a particular frame is independent of frames.

Thus,

Probability of a bowler getting a strike during a single frame
= 41 %
= 0.41\\

Probability of a bowler getting a strike during a double frame


= ((41)/(100) )^2\\= (0.41)^2\\= 0.41 * 0.41\\= 0.1681\\


18%\\ %

User Earl Ferguson
by
8.1k points
4 votes
The percentage of simulations that the bowler would most likely get a strike in each of the two frames would be 18%. The correct option among all the options that are given in the question is the third option or option "C". I hope that this is the answer that has actually come to your great help.
User Eular
by
8.5k points
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