Question

the data set shows the january 1 noon temperatures in degrees Fahrenheit for a particular day in each of the past six years. 28 34 27 42 52 15 the five number summary of the data set is15 27 28 34 42 52 the mean of the data set is 33 what is the sum of the squares of the differences between each data value and the mean? use the table to organize your work

Answer 1

we have that

the mean is 33

so

Fill the table

15 (15-33)=-18 (15-33)^2=324

27 (27-33)=-6 (27-33)^2=36

28 (28-33)=-5 (28-33)^2=25

34 (34-33)=1 (34-33)^2=1

42 (42-33)=9 (42-33)^2=81

52 (52-33)=19 (52-33)^2=361

therefore

The sum of the squares of the differences between each data value and the mean is equal to

Sum=324+36+25+1+81+361

Sum=828