Solution
Explanation:
The relevant relations are ...
external angle A is half the difference of intercepted arcs BC and BD
inscribed angle y° is half the measure of intercepted arc CD
the sum of arcs of a circle is 360°
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Using these relations, we have ...
(a) A = (BC -x°)/2
x° = BC -2A = 114° -2(27°)
x° = 60°
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(b) y° = CD/2 = (360° -BC -BD)/2 = (360° -114° -60°)/2
y° = 93°